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-3x^2-9x+4=0
a = -3; b = -9; c = +4;
Δ = b2-4ac
Δ = -92-4·(-3)·4
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{129}}{2*-3}=\frac{9-\sqrt{129}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{129}}{2*-3}=\frac{9+\sqrt{129}}{-6} $
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